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NEET Sample Paper NEET Sample Test Paper-4

  • question_answer
    The molal freezing point constant for water is \[{{1.86}^{o}}C\] per molarity. Therefore, the freezing point of \[0.1\text{ }M\text{ }NaCl\] solution in water is expected to be

    A)  \[-{{1.86}^{o}}C\]             

    B)  \[-{{0.186}^{o}}C\]

    C)  \[-{{0.372}^{o}}C\]           

    D)  \[+{{0.372}^{o}}C\]

    Correct Answer: C

    Solution :

     For   \[NaCl,\]      \[i=2\] \[\Delta {{T}_{f}}=i\times {{K}_{f}}\times m\] \[=2\times 1.86\times 0.1={{0.372}^{o}}C\] Hence, freezing point of solution \[=0-0.37=-{{0.372}^{o}}C\]


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