question_answer

A particle moves such that its motion is represented by \[a=kx,\] where 'a' is the acceleration and x is displacement and k a constant. The period of oscillation is

A)  \[2\,\pi \sqrt{k}\]                    

B)  \[\frac{2\,\pi }{\sqrt{k}}\]

C)  \[2\,\pi \,k\]                 

D)  \[\frac{2\,\pi }{k}\]

Correct Answer: B

Solution :

\[T=2\pi \,\sqrt{\frac{displacement}{acceleration}}\]             \[=2\pi \sqrt{\frac{x}{kx}}=\frac{2\pi }{\sqrt{k}}\]