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NEET Sample Paper NEET Sample Test Paper-49

  • question_answer
    The period of simple harmonic oscillator is 24 sec. and the initial phase is zero. The time at which the oscillating point would have attained half the amplitude is:

    A) 2 sec                

    B) 2.4 sec

    C) 6 sec                

    D) 12 sec

    Correct Answer: A

    Solution :

    \[x\,\,=\,\,a\text{ }sin\text{ }\omega t\] \[\frac{a}{2}\,\,=\,\,a\,\,\sin \,\omega t\] \[{{\sin }^{-1}}\left( \frac{1}{2} \right)\,\,=\,\,\frac{2\pi }{T}t\] \[\frac{\pi }{6}\,\,=\,\,\frac{2\pi }{T}t\] \[T=\frac{T}{12}\] \[t=\frac{24}{12}\,\,\Rightarrow \,\,2\,\,\sec \]


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