A) 1/2
B) 3/2
C) 5/2
D) 7/2
Correct Answer: C
Solution :
5/2 \[2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}\to {{K}_{2}}S{{O}_{4}}+2MnS{{O}_{4}}\] \[+3{{H}_{2}}O+5\left( O \right)\] \[{{\operatorname{H}}_{2}}{{O}_{2}}+\left( O \right)\to {{H}_{2}}O+{{O}_{2}}\times 5\] \[2KMn{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}+5{{H}_{2}}{{O}_{2}}\to \] \[{{\operatorname{K}}_{2}}S{{O}_{4}}+2MnS{{O}_{4}}+8{{H}_{2}}O+5{{O}_{2}}\] \[\operatorname{Thus}, 2 moles of KMn{{O}_{4}} react with {{H}_{2}}{{\operatorname{O}}_{2}}= 5\]moles \[\operatorname{Here}, 1 mole of KMn{{O}_{4}} =\frac{5}{2}\]
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