A) u
B) 10u
C) 100u
D) 1000u
Correct Answer: B
Solution :
\[\operatorname{Surface} energy \left( U \right) = T.47\pi {{R}^{2}}\] This big drop of radii R is splitted into \[1{{0}^{3}}\]small droplets of radius r \[\frac{4}{3}\pi {{\operatorname{r}}^{3}}={{10}^{3}}\times \frac{4}{3}\pi {{\operatorname{r}}^{3}}\] \[\operatorname{R}=10r\] \[{{\operatorname{E}}_{1}}=1{{0}^{3}}\times 4\pi \times {{\operatorname{r}}^{2}}\times \operatorname{T}\therefore \operatorname{r}=\frac{R}{10}\] \[{{\operatorname{E}}_{1}}=10U\]
You need to login to perform this action.
You will be redirected in
3 sec
