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NEET Sample Paper NEET Sample Test Paper-48

  • question_answer
    The Van't Hoff factor for\[{{\operatorname{BaCl}}_{2}}\], at 0.01 M concentration is 1.98. The percentage dissociation of\[{{\operatorname{BaCl}}_{2}}\]at this concentration is:

    A) 49                    

    B) 69     

    C) 100                  

    D) 98

    Correct Answer: A

    Solution :

    49 \[\begin{align}   & {{\operatorname{BaCl}}_{2}}\rightleftharpoons {{B}^{2+}}+2C{{l}^{-}} \\  & \operatorname{Initial}1\,\,mol\,\,\,\,\,\,\,\,\,\,\,\,\,0\,\,\,\,\,\,\,\,\,\,\,\,0 \\  & \operatorname{After} dissociation1-\alpha \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,~\alpha  \,\,\,\,\,\,\,\,\,\,2\alpha  \\  & \,\,\,\,\,\,\,\,\,\,\,\,\,\operatorname{Total} =1+2\alpha  \\ \end{align}\] \[\operatorname{i}=1+2a\] \[\frac{\operatorname{i}-1}{2}=\alpha \] \[\Rightarrow \alpha =\frac{1.98-1}{2}=\frac{0.98}{2}=0.49\] \[\operatorname{i}.e. 49 %\]


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