A) \[{{\operatorname{NH}}_{3}}\]
B) \[{{\operatorname{BF}}_{3}}\]
C) \[{{\operatorname{AlC}}_{3}}\]
D) \[{{\operatorname{BH}}_{3}}\]
Correct Answer: A
Solution :
\[{{\operatorname{NH}}_{3}}\] In\[{{\operatorname{NH}}_{3}}\], octet of N is complete. Therefore it does need any extra electron. Hence, it is not electron deficient.
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