A) 272V
B) 320V
C) 415V
D) 471V
Correct Answer: D
Solution :
\[\operatorname{I}={{I}_{o}}Sin\omega t={{I}_{\operatorname{o}}}Sin2\pi ft\] \[{{\operatorname{E}}_{max}}=M\frac{di}{dt}=M\frac{d}{dt}\left( {{I}_{o}}sin2\pi ft \right)\] \[{{\operatorname{E}}_{max}}=M{{I}_{o}}2\pi ft\] \[=2\pi M{{I}_{o}}\] \[=2\times 3.14\times 1.5\times 50\] \[= 471 volt\]
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