A) \[{{\operatorname{h}}_{1}}=2{{h}_{2}}=3{{h}_{3}}\]
B) \[{{\operatorname{h}}_{1}}=\frac{{{h}_{2}}}{3}=\frac{{{h}_{3}}}{5}\]
C) \[{{\operatorname{h}}_{2}}=3{{\operatorname{h}}_{1}}\operatorname{and}\,\,{{\operatorname{h}}_{3}}=3{{\operatorname{h}}_{2}}\]
D) \[{{\operatorname{h}}_{1}}={{h}_{2}}={{h}_{3}}\]
Correct Answer: B
Solution :
\[{{\operatorname{h}}_{1}}=\frac{1}{2}g\times {{t}^{2}}_{1}\] \[{{\operatorname{t}}_{1}} = 5sec\] \[{{\operatorname{h}}_{1}}=125m\] \[{{\operatorname{h}}_{2}} =\frac{g}{2}\left[ {{\left( 10 \right)}^{2}} \right]-125=375m\] \[{{\operatorname{h}}_{3}} =\frac{g}{2}\left[ {{\left( 15 \right)}^{2}}-{{\left( 10 \right)}^{2}} \right]=625\] \[{{\operatorname{h}}_{1}}:{{h}_{2}}:{{h}_{3}}\] \[125 : 375 : 625\] \[{{\operatorname{h}}_{1}}:1\frac{{{h}_{2}}}{3}:\frac{{{h}_{3}}}{5}\]
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