A) 1
B) 3
C) 5
D) 4
Correct Answer: B
Solution :
\[In\,\,\Delta ABC\] \[\tan \phi =\frac{x}{h} \] \[\operatorname{x}= h tan \phi \] differentiates w. r. t time \[\frac{dx}{dt}=h\,\,se{{c}^{2}}\phi \frac{d\phi }{dt}\left[ \frac{d\left( tan\phi \right)}{dt}=se{{c}^{2}}\phi \right]\] \[\operatorname{v} = h se{{c}^{2}} \phi \omega \] \[ \omega =\frac{\operatorname{v}}{h\,se{{c}^{2}} \phi }\] \[ \omega =\frac{\operatorname{v}\,co{{s}^{2}}\phi }{h}\] \[ \omega =\frac{40}{30}co{{s}^{2}}30\] \[=\frac{40}{30}\times {{\left( \frac{\sqrt{3}}{2} \right)}^{2}}\] \[= 1 rad/sec\]
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