A) \[{{\operatorname{KO}}_{2}}\]
B) \[{{\operatorname{SiO}}_{2}}\]
C) \[Ti{{O}_{2}}\]
D) \[{{\operatorname{BaO}}_{2}}\]
Correct Answer: A
Solution :
\[{{\operatorname{KO}}_{2}}\] \[{{\operatorname{KO}}_{2}} is superoxide\] Super oxides contain ion \[{{\operatorname{O}}_{2}}^{-}\]which has structure\[:\overset{\mathbf{.}\,\,\,\,\mathbf{.}}{\mathop{HO}}\,\overset{\mathbf{.}\,\,\,\,\mathbf{.}}{\mathop{O}}\,:\]containing 3 electron bond, i.e. It has one unpaired electron and hence it is paramagnetic. Normal oxides such as \[{{\operatorname{TiO}}_{2}}, Ba{{O}_{2}}, Si{{O}_{2}},\] containing ion 02" do not have any unpaired electrons and hence are diamagnetic.
You need to login to perform this action.
You will be redirected in
3 sec
