A) L = 50cm, r= 0.25
B) L = 100cm, r = 0.5 mm
C) L = 200cm, r = 1mm
D) L = 300cm, r = 1.5mm
Correct Answer: A
Solution :
\[\Delta \ell =\frac{\operatorname{F}\ell }{\operatorname{Ay}}\propto \frac{\ell }{{{\operatorname{r}}^{2}}}\] \[\operatorname{a}.\frac{50}{0.25\times 0.25\times {{10}^{-6}}}\operatorname{b}.\frac{100}{0.5\times 0.5\times {{10}^{-6}}}\] \[c.\frac{200}{1\times 1\times {{10}^{-6}}}\operatorname{d}.\frac{300}{1.5\times 1.5\times {{10}^{-6}}}\] a. combination will have largest extension
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