A) 2:3
B) 4:5
C) 3:5
D) 3:4
Correct Answer: D
Solution :
Frequency of the first O.T of closed pipe of lengthy\[{{\ell }_{1}}\] \[{{\operatorname{f}}_{1}}=\frac{3v}{4{{\ell }_{1}}}\] Frequency of the first O.T of open pipe of length \[{{\ell }_{2}}\] \[{{\operatorname{f}}_{2}}=\frac{v}{{{\ell }_{2}}}\] \[\frac{3v}{4{{\ell }_{2}}}=\frac{v}{{{\ell }_{2}}}\] \[\frac{{{\ell }_{1}}}{{{\ell }_{2}}}=\frac{3}{4}\]
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