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NEET Sample Paper NEET Sample Test Paper-47

  • question_answer
    A quarter horse power motor runs at a speed of 600 rpm. Assuming 40% efficiency, the work done by the motor in one rotation will be:

    A) 7.46J               

    B) 7400J  

    C) 7.46erg                         

    D) 74.6J

    Correct Answer: A

    Solution :

    \[\eta =\frac{{{P}_{o}}}{{{P}_{1}}}\] \[{{P}_{o}}=\frac{W}{t}=\eta {{\operatorname{P}}_{1}}\] \[\frac{W}{2\pi \times 600\times \frac{2}{60}\pi }=\frac{40}{100}\times \frac{746}{4}\] 1 HP =746 WATT W=7.46 Joule


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