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NEET Sample Paper NEET Sample Test Paper-46

  • question_answer
    CsBr crystallizes in a body centred cubic lattice. The unit cell length is 436.6 pm. Given that the atomic mass of \[Cs=\text{ }133\] and of \[Br\text{ }=\text{ }80\] amu and Avogadro?s number being\[6.02\times {{10}^{23}}mo{{l}^{-1}}\], the density of CsBr is:

    A) 8.50 g/\[c{{m}^{3}}\]

    B)                    4.25 g/\[c{{m}^{3}}\]

    C)                    42.5 g/\[c{{m}^{3}}\]

    D)                    0.425 g/\[c{{m}^{3}}\]

    Correct Answer: B

    Solution :

    \[\delta \,\,=\,\,\frac{Z\times {{M}_{W}}}{{{N}_{A}}\times \,V}\] \[\delta \,\,=\,\,\frac{1\times 213}{6\times \,{{10}^{23}}\,\,\times \,\,{{(436\times {{10}^{-10}})}^{3}}}\]


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