A) \[{{\omega }_{\min }}=\sqrt{\frac{g}{\mu r}}\]
B) \[{{\omega }_{\min }}=\sqrt{\frac{\mu r}{g}}\]
C) \[{{\omega }_{\min }}=\sqrt{\frac{2g}{\mu r}}\]
D) \[{{\omega }_{\min }}=\sqrt{\frac{gr}{\mu }}\]
Correct Answer: A
Solution :
\[N\,\,=\,\,mr{{\omega }^{2}}\] \[mg\,\,\le \,\,\mu N\] \[\le \,\,\mu mr{{\omega }^{2}}\,\,\Rightarrow \,\,\omega \,\,\le \,\,\sqrt{\frac{g}{\mu r}}\]
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