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NEET Sample Paper NEET Sample Test Paper-46

  • question_answer
    The speed of propagation of a wave in a medium is 300\[m{{s}^{-1}}\]. The equation of motion of point at \[x\text{ }=\text{ }0\] is given by \[y=0.04\] sin \[600\pi t\] (metre). The displacement of a point \[x=75\] cm at \[t\text{ }=\text{ }0.01\] s is-

    A) 0.02 m

    B)                    0.04 m

    C)                    Zero

    D)                    0.028 m

    Correct Answer: B

    Solution :

    \[\because \,\,\,k\,\,=\,\,\frac{\omega }{v}\] \[\omega \,\,=\,\,600\pi \,\,=\,\,2\pi x\,\] \[y=0.04\text{ }sin\text{ }\left( \omega t-kx \right)\] \[y=0.04\text{ }sin\text{ }\left( \omega t-\frac{\omega x}{v} \right)\] \[y=0.04\text{ }sin\text{ }\omega \,(t-\frac{x}{v})\] \[y=0.04\text{ }sin\text{ }600\pi \,(\frac{1}{100}-\frac{75}{100\,\,\times \,\,300})\] \[y=0.04\text{ }sin\text{ }\pi \left( \frac{225}{300} \right)\,\,=\,\,0.04\,m\]


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