A) \[NC{{l}_{3}}\] is hydrolysed and gives \[HOCl\] but \[BC{{l}_{3}}\] is not hydrolysed
B) Both \[NC{{l}_{3}}\] and \[BC{{l}_{3}}\] on hydrolysis gives HCl
C) \[NC{{l}_{3}}\] on hydrolysis gives HOCl but \[BC{{l}_{3}}\] gives \[HCl\]
D) Both \[NC{{l}_{3}}\] and \[BC{{l}_{3}}\] on hydrolysis gives \[HOCl\]
Correct Answer: C
Solution :
\[NC{{l}_{3}}+3HOH\,\,\to \,\,N{{H}_{3}}+\,\,3HOCl\] \[BC{{l}_{3}}+3HOH\text{ }\to \text{ }B{{\left( OH \right)}_{3}}+3HCl\]
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