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NEET Sample Paper NEET Sample Test Paper-45

  • question_answer
    The sulphate of a metal M contains \[9.87\,%\] of M. This sulphate is isomorphous with\[ZnS{{O}_{4}}.7{{H}_{2}}O\]. The atomic weight of M is:

    A) 40.3                 

    B) 36.3

    C) 24.3                             

    D) 11.3

    Correct Answer: C

    Solution :

    As the given sulphate is isomorphous with \[ZnS{{O}_{4}}.7{{H}_{2}}O\] its formula would be \[MS{{O}_{4}}.7{{H}_{2}}O\,.\,m\] is the atomic weight of M, molecular weight of \[MS{{O}_{4}}.7{{H}_{2}}O\,=m+32\] \[+\,64\text{ }+\text{ }126=m\text{ }+\text{ }222\] Hence \[%\,\,of\text{ }M=\frac{m}{m+22}\,\,\times \,\,100=9.87\] or \[100\,m=9.87\,m+222\,\,\times \,\,9.87\] or \[90.13\,m\,\,=\,\,222\,\,\times \,\,9.87\] or \[m=\frac{222\times 9.87}{90.13}=24.3.\]


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