A) \[{{10}^{-}}^{3}\]
B) \[3\,\,\times \,\,{{10}^{-}}^{3}\]
C) \[4\times {{10}^{-}}^{3}\]
D) \[\frac{{{10}^{-3}}}{2}\]
Correct Answer: B
Solution :
Equivalents of \[Al{{(OH)}_{3}}=\frac{0.078}{\left( E=\frac{78}{3} \right)}\,\,=\,\,0.003\] Equivalents of \[HCl=6\,\,\times \,\,{{10}^{-}}^{3}=0.006\] \[\therefore \] Equivalents of \[AlC{{l}_{3}}\] formed \[=\,\,\,0.003=3\,\,\times \,{{10}^{-}}^{3}\]
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