NEET Sample Paper NEET Sample Test Paper-45

  • question_answer
    The ratio of diameters of two wires of same material in\[n:1\]. The length of each wire is 4m. on applying the same load, the increase in length of thin wire will be \[\left( n>1 \right)\] -

    A) \[{{n}^{2}}\] times                  

    B) n times

    C) 2n times                       

    D) \[\left( 2n+1 \right)\] times

    Correct Answer: A

    Solution :

    \[Y=\frac{F/a}{\Delta \ell /\ell }=\frac{F\ell }{a\Delta \ell }\,\,\Rho \,Y\,=\,\,\frac{F\ell \times 4}{\pi {{D}^{2}}\,\times \,\Delta \ell }\] \[\Delta \ell \,\propto \,\frac{1}{{{D}^{2}}}\,\,or\,\,\frac{\Delta {{\ell }^{2}}}{\Delta {{\ell }^{1}}}\,\,=\frac{{{D}^{2}}_{1}}{{{D}^{2}}_{2}}\,=\,\frac{{{n}^{2}}}{1}\]


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