A) \[\frac{3}{40}A\]
B) \[\frac{1}{10}A\]
C) \[\frac{3}{50}A\]
D) \[\frac{3}{10}A\]
Correct Answer: C
Solution :
As \[{{D}_{1}}\] is reversed biased \[{{\operatorname{R}}_{eq}}=40+10=50\,\Omega \] \[\therefore \,\,\,i\,\,=\,\,\frac{3}{50}\,\,A\]
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