2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-45

  • question_answer
    The real angle of dip, if a magnet is suspended at an angle of \[30{}^\circ \] to the magnetic meridian and the dip needle makes an angle of \[45{}^\circ \] with horizontal is

    A) \[{{\tan }^{-1}}\,\,\left( \frac{\sqrt{3}}{2} \right)\]                      

    B) \[{{\tan }^{-1}}\,\,(\sqrt{3})\]

    C) \[{{\tan }^{-1}}\,\,\left( \sqrt{\frac{3}{2}} \right)\]                      

    D) \[{{\tan }^{-1}}\,\,\left( \frac{2}{\sqrt{3}} \right)\]

    Correct Answer: A

    Solution :

    let \[\theta =dip\text{ }angle\] H = horizontal component of the Earth?s field V = vertical component of the Earth?s field Also. \[\tan \theta =\frac{V}{H}\] \[but\,~\,\,\,\,\,\,tan\,45{}^\circ =\,\frac{V}{H\,\cos \,\,30{}^\circ }\] \[\theta ={{\tan }^{-1}}\,\left( \frac{\sqrt{3}}{2} \right)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner