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NEET Sample Paper NEET Sample Test Paper-45

  • question_answer
    When \[100%\] carbon is oxidised to \[C{{O}_{2}}\] the efficiency of such a respiration is?

    A) \[40%\]             

    B) \[60%\]

    C) \[80%\]             

    D) \[100%\]

    Correct Answer: A

    Solution :

    Effeciency of respiration of one molecule of Glucose 1 mol. glucose = 686 Kcal energy conserved It?s complete oxidation produce = 36 ATP \[1\,\,ATP=7.6\text{ }K.Cal.\] \[\frac{36\times 7.6}{686}\,\,\times \,\,100\,\,=\,\,39.88%\]


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