A) \[{{\operatorname{K}}_{{{a}_{2}}}}>{{K}_{{{a}_{1}}}}\]
B) \[{{\operatorname{K}}_{{{a}_{1}}}}>{{K}_{{{a}_{2}}}}\]
C) \[{{\operatorname{K}}_{{{a}_{2}}}}>\frac{1}{{{K}_{{{a}_{1}}}}}\]
D) \[{{\operatorname{K}}_{{{a}_{2}}}}={{K}_{{{a}_{1}}}}\]
Correct Answer: B
Solution :
\[{{\operatorname{K}}_{{{a}_{1}}}}>{{K}_{{{a}_{2}}}}\] For diprotic acid Ka is dissociation contents of acid. \[{{\operatorname{K}}_{{{a}_{1}}}}>{{K}_{{{a}_{2}}}}\] Because it is more difficult to remove a positively charged proton from negative ion due to electrostatic forces. Greater the charge on negative ion, more difficult it becomes to remove a proton.
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