A) \[{{\operatorname{Zn}}^{2+}}\]
B) \[{{\operatorname{Fe}}^{2+}}\]
C) \[{{\operatorname{Ni}}^{2+}}\]
D) \[{{\operatorname{Cu}}^{2+}}\]
Correct Answer: B
Solution :
\[{{\operatorname{Fe}}^{2+}}\] \[{{\operatorname{Cu}}^{2+}} has one unpaired electron.\] \[{{\operatorname{Fe}}^{2+}} has four unpaired electrons.\] \[{{\operatorname{Ni}}^{2+}} has two unpaired electron\] \[{{\operatorname{Zn}}^{2+}} has 0 unpaired electron\]
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