A) 22.4 m/s
B) 5.6 m/s
C) 11.2m/s
D) 6.5 m/s
Correct Answer: C
Solution :
\[{{\operatorname{V}}_{ms}}=\sqrt{\frac{3RT}{M}}\] \[{{\operatorname{V}}_{ms}}\propto \sqrt{T}\] \[{{\operatorname{V}}_{ms}}^{2}\propto \operatorname{T}\]
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