A) \[10m/{{s}^{2}}\]
B) \[5m/{{s}^{2}}\]
C) \[20m/{{s}^{2}}\]
D) \[2.5m/{{s}^{2}}\]
Correct Answer: A
Solution :
\[\operatorname{x}={{u}_{x}}T\] equation of projectile path \[\operatorname{y}=8t-5{{t}^{2}}\]b \[{{\operatorname{V}}_{y}}=\frac{dy}{dt}=8-10t\] \[{{\operatorname{a}}_{y}}=\frac{{{d}^{2}}y}{d{{t}^{2}}}=-10m/{{s}^{2}}\]
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