A) 4.6g
B) 1.6g
C) 2.3g
D) 23g
Correct Answer: C
Solution :
Equimolecular proportion means both gases occupied equal volume \[=\frac{2.24}{2}=1.12\,L\] For \[C{{H}_{4}}:22.4L\text{ }C{{H}_{4}}has\text{ }mass=16\text{ }gm\] \[1.12L\,\,C{{H}_{4}}\text{ }has\text{ }mass\text{ =}\frac{16}{22.4}\times 1.12=0.8gm.\] For \[{{C}_{2}}{{H}_{6}}\] \[22.4L\text{ }{{C}_{2}}{{H}_{6}}\]has mass = 30gm \[1.12L\text{ }{{C}_{2}}{{H}_{6}}\] has mass \[=\frac{30}{22.4}\times 1.12\] \[=\frac{3.0}{2}\,gm=1.5\,gm\] Total mass = 1.5 gm + 0.8 gm = 2.3 gm.
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