A) \[SnC{{l}_{2}}\]
B) \[NO_{2}^{+}\]
C) \[HgC{{l}_{2}}\]
D) \[C{{S}_{2}}\]
Correct Answer: A
Solution :
\[H=\frac{1}{2}(4+2)\] \[=3(s{{p}^{2}})\] 2 b.p. & 1 /,p.
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