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NEET Sample Paper NEET Sample Test Paper-43

  • question_answer
    The vapour pressure of mercury is \[1871.88\times {{10}^{-6}}\] mm Hg at \[27{}^\circ C\]            \[Hg(I)Hg(g)\]The value of equilibrium constant Kc is -

    A) \[{{10}^{-7}}\,M\]                  

    B) \[1871.88\times {{10}^{-6}}\,M\]

    C) \[{{10}^{-5}}M\]                    

    D) \[3.9\times {{10}^{-5}}\,M\]

    Correct Answer: A

    Solution :

    \[{{K}_{p}}={{K}_{C}}{{(RT)}^{\Delta n}};\] 1 atm =760 mm


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