A) \[A\to B\to C~\]
B) \[A\leftarrow B\leftarrow C~\]
C) \[A\to B\leftarrow C~\]
D) \[A\leftarrow B\to C~\]
Correct Answer: C
Solution :
\[D.P.D\text{ }=\text{ }O.P-T.P\] water will move from low D.P.D to high D.P.D or \[{{\psi }_{w}}={{\psi }_{s}}+{{\psi }_{p}}\] where \[{{\psi }_{s}}=-O.P.,{{\psi }_{p}}=T.P.\] So \[{{\psi }_{w}}=-DPD\] water will move from high water potential to low water potential.
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