A) \[{{\operatorname{CrO}}^{2-}}_{4}\]
B) \[\operatorname{Cr}{{\left( OH \right)}_{3}}\]
C) \[\operatorname{Cr},{{\operatorname{O}}^{2-}}_{3}\]
D) \[\operatorname{Cr}{{\left( OH \right)}_{2}}\]
Correct Answer: A
Solution :
\[{{\operatorname{CrO}}_{3}} + 2HCl \to Cr{{O}_{2}}C{{l}_{2}} + {{H}_{2}}O\] \[{{\operatorname{CrO}}_{3}} + 2NaOH \to NaQ+{{H}_{2}}O\] From above reaction, it has been seen clearly.
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