A) \[{{\operatorname{CH}}_{3}}C{{H}_{2}}C{{H}_{2}}Cl\]
B) \[{{\operatorname{CH}}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl\]
C) \[{{\operatorname{CH}}_{3}}CH\left( C{{H}_{3}} \right)C{{H}_{2}}Cl\]
D) \[{{(C{{H}_{3}})}_{3}}CCl\]
Correct Answer: B
Solution :
For isometric halides, boiling point decreases with increase in branching. Therefore \[{{\operatorname{CH}}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl\]has the highest. Boiling point.
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