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NEET Sample Paper NEET Sample Test Paper-42

  • question_answer
    A cylindrical tube closed at one end contain air. It produces the fundamental note of frequency 512Hz. If the tube is opened at both ends, then the fundamental frequency that can be excited is:

    A) 256 Hz             

    B) 512 Hz

    C) 1024 Hz                       

    D) 128 Hz

    Correct Answer: C

    Solution :

    Fundamental frequency of closed pipe \[{{\operatorname{f}}_{o}}=\frac{v}{4L}\] \[512=\frac{v}{4L}\]                 ?.(1) Fundamental frequency of open pipe \[{{\operatorname{f}}_{o}}=\frac{v}{2L}\]                    ?.(2) By (1) and (2) \[{{\operatorname{f}}_{o}}=1024Hz\]


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