NEET Sample Paper NEET Sample Test Paper-41

  • question_answer
    A particle of mass M, attached to one end of a spiral spring describes S.H.M. When the particle is passing through the mean position another particle of mass m is fixed on mass M. The ratio of frequency of the system in the two cases is:

    A) \[\frac{M}{m+M}\]       

    B)   \[\sqrt{\frac{M}{m+M}}\]

    C) \[\frac{m+M}{M}\]                   

    D) \[\sqrt{\frac{m+M}{M}}\]

    Correct Answer: D

    Solution :

    \[f=\frac{1}{2\pi }\sqrt{\frac{k}{M}}\] When only particle of M attached to spring \[{{f}_{a}}=\frac{1}{2\pi }\sqrt{\frac{k}{M}}\]              ?..(1) When another particle of mass m attached to it     \[{{f}_{b}}=\frac{1}{2\pi }\sqrt{\frac{k}{m+M}}\]                     ?.(2) \[\left( 1 \right)\div \left( 2 \right)\] \[\frac{{{f}_{a}}}{{{f}_{b}}}=\sqrt{\frac{m+M}{M}}\]


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