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NEET Sample Paper NEET Sample Test Paper-41

  • question_answer
    A physical quantity is determined P\[=\frac{\sqrt{ab{{c}^{2}}}}{{{d}^{3}}{{e}^{1/3}}}\] measuring a, b, c, d and e separately with the percentage error of 2%, 3%, 2%, 1% and 6% respectively. Minimum amount of error is contributed by the measurement:

    A)  b                    

    B)  a         

    C)  d                    

    D)  e

    Correct Answer: B

    Solution :

    \[P=\frac{\sqrt{ab{{c}^{2}}}}{{{d}^{3}}{{e}^{1/3}}}\] % error of following quantity \[a=\frac{1}{2}\times 1%,\,\,\,\,\,\,b=\frac{1}{2}\times 3=5.1%\] \[c=\frac{2\times 1\times 2}{2}%=2%\,\,\,\,\,\,\,\,\,d=\,3\times 1%\] \[e=\frac{1}{3}\times 6=2%\]


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