A) \[NaCl<LiCl<BeC{{l}_{2}}\]
B) \[BeC{{l}_{2}}<NaCl<LiCl\]
C) \[BeC{{l}_{2}}<LiCl<NaCl\]
D) \[LiCl<NaCl<BeC{{l}_{2}}\]
Correct Answer: A
Solution :
Covalent character in a compound is found by Fajan's Rule. Greater the size of the cation, more will be the ionic character and (ii) Greater the size of anion, more will be its covalent character and charge on the cation is dominant over the size of the cation. (iii) Greater the charge on the cation, more will be its covalent character Hence\[BeC{{l}_{2}}>LiCl>NaCl\](in covalent character)
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