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NEET Sample Paper NEET Sample Test Paper-40

  • question_answer
    The value of equilibrium constant of the reaction, \[HI(g)\rightleftharpoons \frac{1}{2}{{H}_{2}}(g)+\frac{1}{2}{{I}_{2}}(g)\]is 8.0.  The  equilibrium constant of the reaction\[{{H}_{2}}(g)+{{I}_{2}}(g)\rightleftharpoons 2HI(g)\]will be

    A) \[\frac{1}{64}\]

    B)  16

    C) \[\frac{1}{8}\]

    D) \[\frac{1}{16}\]

    Correct Answer: A

    Solution :

     For \[HI\rightleftharpoons \frac{1}{2}{{H}_{2}}+\frac{1}{2}{{I}_{2}};\,\,{{K}_{{{c}_{1}}}}=8\] Reverse given eqn. and multiply by 2. \[\therefore \,\]For \[{{H}_{2}}+{{I}_{2}}\rightleftharpoons 2HI;{{K}_{{{C}_{2}}}}={{\left( \frac{1}{{{K}_{{{c}_{1}}}}} \right)}^{2}}\] \[={{\left( \frac{1}{8} \right)}^{2}}=\frac{1}{64}\]


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