A) \[-221.1\,kJ\,mo{{l}^{-1}}\]
B) \[-339.3\text{ }kJ\text{ }mo{{l}^{-1}}\]
C) \[-439.3\text{ }kJ\,mo{{l}^{-1}}\]
D) \[-523.2\text{ }kJ\text{ }mo{{l}^{-1}}\]
Correct Answer: B
Solution :
\[\Delta {{\Eta }^{o}}=-382.64\,kJ\,mo{{l}^{-1}}\] Give that, \[\Delta {{S}^{o}}=-145.6\,J\,{{K}^{-1}}\,mo{{l}^{-1}}\] \[=-145.6\times {{10}^{-3}}\,kJ\,{{K}^{-1}}\] or \[\Delta {{G}^{o}}=-382.64-(298\times 1-145.6\times {{10}^{-3}})\] \[=-339.3\,kJ\,mo{{l}^{-1}}.\]
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