2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-40

  • question_answer
    The Young's modulus of steel is twice that of brass. Two wires of the same length and of the same area of cross section, one of steel and another of brass are suspended from the same roof. If we want the lower ends of the wires to be at the same level, then the weights added to the steel and brass wires must be in the ratio of

    A)  1 : 1

    B)  1 : 2

    C)  2 : 1

    D)  4 : 1

    Correct Answer: C

    Solution :

    Young modulus \[Y=\frac{W.I}{A\Delta I}\] \[l,A\]and\[\Delta l\]are the same for both the wires. \[Y\propto W\] \[\frac{{{Y}_{s}}}{{{Y}_{b}}}=\frac{{{W}_{s}}}{{{W}_{b}}}=\frac{2}{1}\] \[{{W}_{s}}:{{W}_{b}}=2:1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner