2. Sample Papers
  3. NEET

NEET Sample Paper NEET Sample Test Paper-40

  • question_answer
    A body of mass m is placed on the earth's surface. It is taken from the earth's surface to a height \[h=3R.\]The change in gravitational potential energy of the body is

    A) \[\frac{2}{3}mgR\]

    B)  \[\frac{3}{4}mgR\]

    C) \[\frac{mgR}{2}\]

    D)  \[\frac{mgR}{4}\] 

    Correct Answer: B

    Solution :

     \[\Delta U=\frac{mgh}{1+\frac{h}{R}}=\frac{mg\times 3R}{1+\frac{3R}{R}}=\frac{3}{4}mgR\]


You need to login to perform this action.
You will be redirected in 3 sec spinner