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NEET Sample Paper NEET Sample Test Paper-3

  • question_answer
    A gaseous mixture contains \[56g\,{{N}_{2}};\] \[44g\,C{{O}_{2}}\] and \[16g\,C{{H}_{4}}\]. The total pressure of the mixture is\[720\text{ }mm\text{ }Hg\]. What is the partial pressure of \[C{{H}_{4}}\]?

    A)  \[220\,mm\]                

    B)  \[540\text{ }mm\]

    C)  \[180\text{ }mm\]        

    D)  \[100\text{ }mm\]

    Correct Answer: C

    Solution :

        \[56\,g\,\,{{N}_{2}}=\frac{56}{28}=2\,mol\] \[44\,g\,\,C{{O}_{2}}=\frac{44}{44}=1\,mol\] \[16\,g\,\,C{{H}_{4}}=\frac{16}{16}=1\,mol\] Partial pressure of \[C{{H}_{4}}=\frac{{{n}_{C{{H}_{4}}}}}{{{n}_{{{N}_{2}}}}+{{n}_{C{{O}_{2}}+}}{{n}_{C{{H}_{4}}}}}\times P\]                                 \[=\frac{1}{2+1+1}\times 720\]                                 \[=180\,mm\]  


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