question_answer

The equivalent capacitance between P and Q on the figure is;            

A)  \[\frac{A\,{{\varepsilon }_{0}}}{2d}\]                    

B)  \[\frac{3A\,{{\varepsilon }_{0}}}{2d}\]

C)  \[\frac{2A\,{{\varepsilon }_{0}}}{2d}\]                  

D)  \[\frac{5A\,{{\varepsilon }_{0}}}{3d}\]

Correct Answer: D

Solution :

    The equivalent circuit can be given as             \[\therefore \]     \[{{C}_{eq}}=C+\frac{C\times 2C}{C+2C}\]                                 \[=C+\frac{2}{3}C=\frac{5}{3}C=\frac{5A{{\varepsilon }_{0}}}{3d}\]