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NEET Sample Paper NEET Sample Test Paper-3

  • question_answer
    The same mass of copper is drawn into two wires 1mm, 2mm thick two wires connected in series and current is passed through them. Heat produced in the wire is in the ratio:

    A)  \[2:1\]                         

    B)  \[1:16\]

    C)  \[4:1\]                         

    D)  \[16:1\]

    Correct Answer: D

    Solution :

        \[H={{i}^{2}}RT={{i}^{2}}\left( \frac{\rho l}{A} \right)t\] \[=\frac{{{i}^{2}}\rho Vt}{{{A}^{2}}}\] (V = volume) \[\Rightarrow \]   As,       \[\rho V\] = mass, t = time and      i = current (constants) \[\Rightarrow \]               \[H\propto \frac{1}{{{r}^{4}}}\] \[\therefore \]  \[\frac{{{H}_{1}}}{{{H}_{2}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{4}}={{\left( \frac{2}{1} \right)}^{4}}=\frac{16}{1}\]


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