A) Displacement of the particle is 30m.
B) Distance covered by the particle is 30m.
C) Distance covered by the particle is \[2.5m\]
D) None of these
Correct Answer: C
Solution :
Displacement of the particle during third second of the motion (i.e., between \[t=2s\] and \[t=35\]) is zero. Hence, t = 2.55 is the turning point of the motion. for distance, \[{{S}_{t}}=2=25\times 2\] \[=\frac{1}{2}\times 10\times {{(2)}^{2}}=30m\] and \[{{S}_{t}}=2.5=25\times 25-\frac{1}{2}\times 10\times {{(2.5)}^{2}}=31.25m\] Here point to be noted that during 3rd second of motion, for half time (i.e. 0.55) the particle will go up and for the other half time (i.e. \[0.55\]), the particle will go lower, here the distance gap and time gap will remain same. Hence, distance covered by the particle during third second of motion \[=2(31.25-30)=2.5\,m\]
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