NEET Sample Paper NEET Sample Test Paper-39

  • question_answer \[A{{l}_{2}}{{O}_{3}}\]is reduced by electrolysis at low potentials and high currents. If \[4.0\times {{10}^{4}}\]amperes of cur- rent is passed through molten \[A{{l}_{2}}{{O}_{3}}\]for 6 hours, what mass of aluminium is produced? (Assume 100% current efficiency. At mass of Al = 27g \[mo{{l}^{-1}}\])

    A) \[1.3\times {{10}^{4}}g\]

    B) \[1.3\times {{10}^{4}}g\]

    C) \[8.05\times {{10}^{4}}g\]

    D) \[2.4\times {{10}^{5}}\,g\]

    Correct Answer: C

    Solution :

     Eq. of Al formed \[=\frac{m}{F}=\frac{it}{96500}\] \[\therefore \] \[{{m}_{Al}}=\frac{4\times {{10}^{4}}\times 6\times 60\times 60\times 27}{96500\times 3}\left( E=\frac{27}{3} \right)\] \[\therefore \]\[{{m}_{Al}}=8.05\times {{10}^{4}}g\]


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