• # question_answer The product of the following reaction are $C{{H}_{3}}C\equiv C\,.C{{H}_{2}}C{{H}_{3}}=\xrightarrow[(ii)Hydrolysis]{(i){{O}_{3}}}?$ A) $C{{H}_{3}}COOH+C{{H}_{3}}COC{{H}_{3}}$B) $C{{H}_{3}}COOH+C{{H}_{3}}C{{H}_{2}}COOH$C) $C{{H}_{3}}CHO+C{{H}_{3}}C{{H}_{2}}CHO$D) $C{{H}_{3}}COOH+C{{O}_{2}}$

Solution :

$C{{H}_{3}}-C=C-C{{H}_{2}}-C{{H}_{3}}\xrightarrow{{{O}_{3}}}$ The glyoxal formed as an intermediate is oxidised by ${{H}_{2}}{{O}_{2}}$to give the acids.

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