question_answer

The product of the following reaction are \[C{{H}_{3}}C\equiv C\,.C{{H}_{2}}C{{H}_{3}}=\xrightarrow[(ii)Hydrolysis]{(i){{O}_{3}}}?\]

A) \[C{{H}_{3}}COOH+C{{H}_{3}}COC{{H}_{3}}\]

B) \[C{{H}_{3}}COOH+C{{H}_{3}}C{{H}_{2}}COOH\]

C) \[C{{H}_{3}}CHO+C{{H}_{3}}C{{H}_{2}}CHO\]

D) \[C{{H}_{3}}COOH+C{{O}_{2}}\]   

Correct Answer: B

Solution :

 \[C{{H}_{3}}-C=C-C{{H}_{2}}-C{{H}_{3}}\xrightarrow{{{O}_{3}}}\] The glyoxal formed as an intermediate is oxidised by \[{{H}_{2}}{{O}_{2}}\]to give the acids.