• # question_answer In the hydrocarbon, $\underset{6}{\mathop{C}}\,{{H}_{3}}-\underset{5}{\mathop{C}}\,H=\underset{4}{\mathop{C}}\,H-\underset{3}{\mathop{C}}\,{{H}_{2}}-\underset{2}{\mathop{C}}\,\equiv \underset{1}{\mathop{C}}\,H$ the state of hybridization of carbons 1, 3 and 5 are in the following sequence A) $sp,s{{p}^{3}},s{{p}^{2}}$B) $sp,s{{p}^{2}},s{{p}^{3}}$C) $s{{p}^{3}},s{{p}^{2}},sp$D) $s{{p}^{2}},sp,s{{p}^{3}}$

Correct Answer: A

Solution :

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