A) \[M{{n}^{4+}}\]and\[{{O}_{2}}\]
B) \[M{{n}^{2+}}\]and\[{{O}_{2}}\]
C) \[M{{n}^{2+}}\]and\[{{O}_{3}}\]
D) \[M{{n}^{4+}}\]and\[Mn{{O}_{2}}\]
Correct Answer: B
Solution :
The reaction of aqueous \[KMn{{O}_{4}}\]with \[{{H}_{2}}{{O}_{2}}\]in acidic medium is \[3{{H}_{2}}S{{O}_{4}}+2KMn{{O}_{4}}+5{{H}_{2}}{{O}_{2}}\xrightarrow{{}}\] \[5{{O}_{2}}+2MnS{{O}_{4}}+8{{H}_{2}}O+{{K}_{2}}S{{O}_{4}}\] In the above reaction, \[KMn{{O}_{4}}\]oxidises \[{{H}_{2}}{{O}_{2}}\]to and\[MnO_{4}^{-}\]gets reduced to \[M{{n}^{2+}}\]ion as \[MnS{{O}_{4}}.\]Hence, aqueous solution of\[KMn{{O}_{4}}\]with \[{{H}_{2}}{{O}_{2}}\]yields \[M{{n}^{2+}}\]and \[{{O}_{2}}\]in acidic conditions.
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